If `siny=xsin(a+y),` prove that `(dy)/(dx)=(sin^2(a+y))/(sina)`

Explanation

To prove that \(\frac{dy}{dx} = \frac{\sin^2(a+y)}{\sin a}\) given that \(\sin y = x \sin(a+y)\), we will follow these steps:

### Step 1: Differentiate both sides with respect to \(x\)

Starting from the equation:
\[ \sin y = x \sin(a+y) \]
...