Home
Class 12
CHEMISTRY
The rate constant for the order reaction...

The rate constant for the order reaction increases from `4 xx 10^(-2)` to `24 xx 10^(-2)` when the temperature changes from 300K to 350 K. Calculate energy of activation for this reaction.

Promotional Banner

Similar Questions

Explore conceptually related problems

The rate constant for a first order reaction increases from 4 xx 10^(-2) to 8 xx 10^(-2) when the temperature changes from 27^(@) C to 37^(@) C. Calculate energy of activation for the reaction.

The rate constant of a first order reaction increases from 4 xx 10 ^(-2)to 8xx10^(-2) when the temperatur changes from 27^(@) C to 37 ^(@) C. Calculate the energy of activation (Ea ).Log 2= 0.301), log 3 = 0. 4771, log 4= 0. 6021

The rate of a reaction increases four times when the temperature changes from 300K to 320 K. Calculate the energy of activation of the reaction. (R=8.314JK^(-1)mol^(-1))

(a) Explain the following terms : (i) Order of a reaction (ii) Molecularity of a reaction (b) The rate of a reaction increases four times when the temperature changes from 300 K to 320 K. Calculate the energy of activation of the reaction, assuming that it does not change with temperature. (R = 8.314 J K^(-1) mol^(-1))

(a) Explain the following terms : (i) Order of a reaction (ii) Molecularity of a reaction (b) The rate of a reaction increases four times when the temperature changes from 300 K to 320 K. Calculate the energy of activation of the reaction, assuming that it does not change with temperature. (R = 8.314 J K^(-1) mol^(-1))

The rate of a particular reaction quadruples when the temperature changes from 293 K to 313 K. Calculate the energy of activation for such a reaction.