Show that the focal chord, of parabola `y^2 = 4ax`, that makes an angle `alpha` with the x-axis is of length `4a cosec^2 alpha`.

Statement 1: The length of focal chord of a parabola y^(2)=8x making on an angle of 60^(@) with the x-axis is 32. Statement 2: The length of focal chord of a parabola y^(2)=4ax making an angle with the x -axis is 4a cos ec^(2)alpha

Length of focal of the parabola y^(2)=4ax making an angle alpha with the axis of the parabola is

Statement 1: The length of focal chord of a parabola y^2=8x making on an angle of 60^0 with the x-axis is 32. Statement 2: The length of focal chord of a parabola y^2=4a x making an angle with the x-axis is 4acos e c^2alpha

Statement 1: The length of focal chord of a parabola y^2=8x making on an angle of 60^0 with the x-axis is 32. Statement 2: The length of focal chord of a parabola y^2=4a x making an angle with the x-axis is 4acos e c^2alpha

Statement 1: The length of focal chord of a parabola y^2=8x making on angle of 60^0 with the x-axis is 32. Statement 2: The length of focal chord of a parabola y^2=4a x making an angle with the x-axis is 4acos e c^2alpha

Statement 1: The length of focal chord of a parabola y^2=8x mkaing on angle of 60^0 with the x-axis is 32. Statement 2: The length of focal chord of a parabola y^2=4a x making an angle with the x-axis is 4acos e c^2alpha

Find the length of the normal chord of a parabola y^2 = 4x , which makes an angle 45^@ with its axes.

The length of a focal chord of the parabola y^(2)=4ax making an angle theta with the axis of the parabola is (a>0) is: