Three positive numbers form a GP. If the middle number is increased by 8, the three numbers form an AP. If the last number is also increased by 64 along with the previous increase in the middle number, the resulting numbers form a GP again.Then :-

(4)5Three positive numbers form a GP. If the middlenumber is increased by 8, the three numbers forman AP. If the last number is also increased by 64along with the previous increase in the middlenumber, the resulting numbers form a GP again.Then :-(1) common ratio = 3(2) first number = 3(4) first number = 5(3) common ratio = -5or

(4)5Three positive numbers form a GP. If the middlenumber is increased by 8, the three numbers forman AP. If the last number is also increased by 64along with the previous increase in the middlenumber, the resulting numbers form a GP again.Then :-(1) common ratio = 3(2) first number(3) common ratio = -5 (4) first number = 5Suppose that all the terms of an arithmetic

Three numbers form an increasing G.P. If the middle number is doubled, then the new numbers are in A.P. The common ratio of the G.P. is

Three positive numbers form a G.P. If the second term is increased by 8, the resulting sequence is an A.P. In turn, if we increase the last term of this A.P. by 64, we get a G.P. Find the three numbers .

Three positive numbers form an increasing GP. If the middle terms in this GP is doubled, the new numbers are in AP. Then, the common ratio of the GP is

Three positive numbers form an increasing GP. If the middle terms in this GP is doubled, the new numbers are in AP. Then, the common ratio of the GP is

Three positive numbers form an increasing GP. If the middle terms in this GP is doubled, the new numbers are in AP. Then, the common ratio of the GP is

Three positive numbers form an increasing GP. If the middle terms in this GP is doubled, the new numbers are in AP. Then, the common ratio of the GP is