`lim_(x rarr pi/2) tanx log_e sinx=`

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lim_ (x rarr (pi) / (2)) tan x log_ (e) sin x =

lim_ (x rarr (pi) / (2)) tan x log sin x

lim_(x rarr 0) x log_(e) (sinx) is equal to

lim_(xrarr pi//2)([x/2])/(log_e(sinx)) (where [.] denotes the greatest integer function)

lim_(xrarr pi/2) ((1-tanx//2)(1-sinx))/((1-tanx//2)(pi-2x)^3)

The value of lim_(x rarr 1) sec\ pi/(2x) log_e x is

lim_(x rarr -pi) |x+pi|/sinx is

Evaluate the following limit : lim_(x rarr pi/2)(pi/2-x)tanx .