`I fy=cos(sinx^2),t h e na t x=sqrt(pi/2)(dy)/(dx)=`

If y=cos(sinx^2) ,then at x=sqrt((pi)/(2)) , (dy)/(dx)=

If y=cos(sinx^2) ,then at x=sqrt((pi)/(2)) , (dy)/(dx)=

If x=sin tcos 2t , y=cos t sin 2t ,then " at " t= (pi)/(4) ,(dy)/(dx)=

If x=sin tcos 2t,y= cos tsin 2t ,then " at " t= (pi)/(4) ,(dy)/(dx)

If y=cos(sinx^(2)), " then " (dy)/(dx) " at " x=sqrt(pi/2) is

If x=cos t,y=log_(e)t then at t=(pi)/(2),(d^(2)y)/(dx^(2))+((dy)/(dx))^(2)=

If y=|cosx|+|sinx|,t h e n(dy)/(dx)a tx=(2pi)/3 is (1-sqrt(3))/2 (b) 0 (c) 1/2(sqrt(3)-1) (d) none of these

If y=|cosx|+|sinx|,t h e n(dy)/(dx)a tx=(2pi)/3 is (1-sqrt(3))/2 (b) 0 (c) 1/2(sqrt(3)-1) (d) none of these

If x= 2cost+cos 2t,y=2sin t-sin 2t ,then " at " t= ( pi)/(4) ,(dy)/(dx)

If x=e^(cos2t) and y=e^(sin2t) , then prove that (dy)/(dx)=(-ylogx)/(x logy) .