Two cards are drawn one after another from a pack of 52 ordinary cards. Find the probability that the first card is an ace and the second drawn is an honour cards.

Explanation

There are total `52` cards.

There are `4` aces and `16` honour cards in cluding `4` aces.

`:.` Probability of drawing first card as an ace, `P(A) = 4/52 = 1/13`

Now, there are `51` cards remaining out of which there are `15` honour cards as one ace we have already drawn.

`:.` Probability of drawing an honour card `= 15/51 = 5/17`

So, the required probability `= 1/13*5/17 = 5/221.`