Home
Class 12
CHEMISTRY
The specific conductivity of a saturated...

The specific conductivity of a saturated solution of `Kl_(3)` is `4.59xx10^(-6)"ohm"^(-1)"cm"^(-1)` and its molar conductanc eis `"1.53 ohm"^(-1)"cm"^(2)"mol"^(-1)`. The `K_("sp")` of `Kl_(3)` will be

A

`4xx10^(-12)`

B

`27xx27xx10^(-9)`

C

`9xx10^(-6)`

D

`4xx10^(-4)`

Text Solution

Verified by Experts

The correct Answer is:
C

`KI_(3) hArr K^(+)I_(3)^(-)`
`K_("sp")=S^(2)`
`lambda_(m)=(Kxx1000)/(S) rArr S=(4.59xx10^(-6)xx1000)/(1.53)`
`S=3xx10^(-3),K_("sp")=9xx10^(-6)`
Promotional Banner

Similar Questions

Explore conceptually related problems

The conductivity of saturated solution of BaSO_(4) is 3.06xx10^(-6) ohm^(-1) cm^(-1) and its equivalent conductance is 1.53 ohm^(-1) cm^(2) "equiv"^(-1) . The K_(sp) for BaSO_(4) will be:

The conductivity of a saturated solution of BaSO_4 is 3. 06 xx 10^(-6) "ohm"^(-1) cm^(-1) and its equivalent conductance is 1.53 "ohm"^(-1) cm^2 equiv^(-1) . The K_(sp) for BaSO_4 will be .

At 298K the electrolytic conductivity of a 0.2 M KCl solution is 2.5xx10^(-2) ohm^(-1)cm^(-1) compute its molar c onductivity.

Specific conductance of 0.1 M NaCl solution is 1.01xx10^(-2) ohm^(-1) cm^(-1) . Its molar conductance in ohm^(-1) cm^(2) mol^(-1) is

The specific conductance of 0.1 M NaCl solution is 1.06 xx 10^(-2) ohm^(-1) cm^(-1) . Its molar conductance in ohm^(-1) cm^(2) mol^(-1) is

The specific conductivity of a saturated solution of AgCl is 3.40xx10^(-6) ohm^(-1) cm^(-1) at 25^(@)C . If lambda_(Ag^(+)=62.3 ohm^(-1) cm^(2) "mol"^(-1) and lambda_(Cl^(-))=67.7 ohm^(-1) cm^(2) "mol"^(-1) , the solubility of AgC at 25^(@)C is:

The specific conductance and equivalent conductance of a saturated solution of BaSO_(4) are 8xx10^(-5)ohm^(-1)cm^(-1) and 8000 ohm^(-1)cm^(2)"equi"^(-1) respectively. Hence K_(sp) of BaSO_(4) is

If conductivity of 0.1 mol / dm^3 solution of KCl is 1.3 * 10^(-2) S cm^(-1) at 298 K then its molar conductivity will be