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The volume of air (O(2) = 20%) necessary...

The volume of air `(O_(2) = 20%)` necessary for the complete combustion of 20 L of propane is :-

A

500 L

B

60 L

C

80 L

D

100 L

Text Solution

Verified by Experts

The correct Answer is:
A
`underset(20L)(C_(3)H_(8))+underset(100L)(5O_(2))to underset(0)(3CO_(2))+underset(0)(4H_(2)O)`
`100 LO=(20)/(100)xxV_("air")`
`500=V_("air")`
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