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Two body of same mass 'm' each are place...

Two body of same mass 'm' each are placed at distance d from each other, then gravitational force between them is F. If 50% mass is transferred from one body to another and distance between them increased by 50% then new gravitational force between them will be :

A

`(3F)/(4)`

B

`F/9`

C

`F/3`

D

`(4F)/(9)`

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The correct Answer is:
To solve the problem, we need to analyze the changes in mass and distance and their effect on gravitational force. Let's break it down step by step. ### Step 1: Initial Setup We start with two bodies, each having mass \( m \), separated by a distance \( d \). The gravitational force \( F \) between them can be expressed using Newton's law of gravitation: \[ F = \frac{G m_1 m_2}{r^2} \] where \( G \) is the gravitational constant, \( m_1 = m \), \( m_2 = m \), and \( r = d \). ### Step 2: Calculate Initial Gravitational Force Substituting the initial values into the formula: \[ F = \frac{G m \cdot m}{d^2} = \frac{G m^2}{d^2} \] ### Step 3: Mass Transfer Now, we transfer 50% of the mass from one body to the other. After the transfer: - The first body will have \( m - \frac{m}{2} = \frac{m}{2} \). - The second body will have \( m + \frac{m}{2} = \frac{3m}{2} \). ### Step 4: Increase in Distance The distance between the two bodies is increased by 50%. The new distance \( r' \) becomes: \[ r' = d + 0.5d = 1.5d = \frac{3d}{2} \] ### Step 5: Calculate New Gravitational Force Now, we can calculate the new gravitational force \( F' \) using the new masses and the new distance: \[ F' = \frac{G m_1' m_2'}{(r')^2} \] Substituting the new values: \[ F' = \frac{G \left(\frac{3m}{2}\right) \left(\frac{m}{2}\right)}{\left(\frac{3d}{2}\right)^2} \] ### Step 6: Simplifying the New Force Equation Calculating the denominator: \[ \left(\frac{3d}{2}\right)^2 = \frac{9d^2}{4} \] Now substituting this back into the equation for \( F' \): \[ F' = \frac{G \cdot \frac{3m}{2} \cdot \frac{m}{2}}{\frac{9d^2}{4}} = \frac{G \cdot \frac{3m^2}{4}}{\frac{9d^2}{4}} = \frac{3G m^2}{9d^2} = \frac{G m^2}{3d^2} \] ### Step 7: Relating New Force to Initial Force Recall that the initial gravitational force \( F \) was: \[ F = \frac{G m^2}{d^2} \] Thus, we can express \( F' \) in terms of \( F \): \[ F' = \frac{1}{3} F \] ### Conclusion The new gravitational force \( F' \) after transferring 50% of the mass from one body to another and increasing the distance by 50% is: \[ F' = \frac{F}{3} \] ### Final Answer The new gravitational force between the two bodies is \( \frac{F}{3} \). ---

To solve the problem, we need to analyze the changes in mass and distance and their effect on gravitational force. Let's break it down step by step. ### Step 1: Initial Setup We start with two bodies, each having mass \( m \), separated by a distance \( d \). The gravitational force \( F \) between them can be expressed using Newton's law of gravitation: \[ F = \frac{G m_1 m_2}{r^2} \] where \( G \) is the gravitational constant, \( m_1 = m \), \( m_2 = m \), and \( r = d \). ...
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