A soap bubble of radius 1//sqrtpi "cm" i...

A soap bubble of radius `1//sqrtpi "cm"` is expanded to radius `2//sqrtpi "cm".` Calculate the work done. Surface tension of soap solution `=30 "dyne"" "cm^(-1).`

180 ergs

360ergs

720 ergs

960 ergs

Text Solution

Verified by Experts

The correct Answer is:

`W= 8pi T(r_(2)^(2) -r_(1)^(2)) =8pi T[ ((2)/(sqrtpi))^(2)- ((1)/(sqrtpi))^(2)]`
`therefore W =8xxpi 30xx3/pi =720 erg `

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