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Both the strings, shown in figure, are m...

Both the strings, shown in figure, are made of same material and have same cross-section. The pulleys are light. The wave speed of transverse wave in the string `AB` is `v_(1)` and in `CD` it is `v_(2)`, the `v_(1)//v_(2)` is

A

1

B

2

C

`sqrt2`

D

`(1)/(sqrt2)`

Text Solution

Verified by Experts

The correct Answer is:
D
`v=sqrt((T)/(u))`
[T = tension forse]
[`mu` = mass per unit length]
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