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The resultant ampiltude of a vibrating ...

The resultant ampiltude of a vibrating particle by the superposition of the two waves `y_(1) = a sin ( omega t + (pi)/(3)) and y_(2) = a sin omega t` is :

A

a

B

`sqrt(2)_(a)`

C

`2a`

D

`sqrt(3)_(a)`

Text Solution

Verified by Experts

The correct Answer is:
D
Resultant amplitude `= 2a cos ((pi//3)/(2)) = sqrt(3a)`
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