An electromagnetic wave going through va...

An electromagnetic wave going through vacuum is described by `vecE=E_(0)sin(kx-wt) and vecB=B_(0)sin(kx-wt)`. Which of the following equation is true?

`E_(0)k=B_(0)omega`

`E_(0)omega=B_(0)k`

`E_(0)B_(0)=omega k`

`E_(0)omegak=B_(0)`

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The correct Answer is:

We know that `E_(0)=CB_(0)`, where C is velocity of light
thus, `E_(0)=(omega)/(K)B_(0) because C=(omega)/(K)" or "E_(0)K=B_(0)omega`

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