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A nuclear reaction along with the masses...

A nuclear reaction along with the masses of the particle taking part in it is as follows
`underset("1.002 amu")(A)+underset("1.004 amu")(B) to underset("1.001 amu")(C)+underset("1.003 amu")(D)+QMeV`
the energy Q is liberated in the reaction is

A

1.234 MeV

B

0.931 MeV

C

0.465 MeV

D

1.862 MeV

Text Solution

Verified by Experts

The correct Answer is:
D
`Q=(1.002+1.004-1.001-1.003)(931.5)MeV`
`=1.863MeV`
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