In the circuit shown in figure, when the input voltage of the base resistance is 10 V, `V_(be)` is zero and `V_(ce)` is also zero. Then

Options

A. 133
B. 1330
C. 13.3
D. 1.33

Answer

A

Explanation

`I_(B)=(V_(i))/(R_(B))=(10V)/(400xx10^(3)Omega)=25muA`
`I_(C)=(10V)/(3kOMega)=3.33mAimplies beta=(I_(C))/(I_(B))=(3.33xx10^(-3))/(25xx10^(-6))=133`