`H_(2)N - CH_(2) - CH_(2) - NH_(2)` serves as

Options

A. Monodentate ligand
B. Chelating ligand
C. Anionic ligand
D. Cationic ligand

Answer

To solve the question regarding the compound \( H_2N - CH_2 - CH_2 - NH_2 \), we will follow these steps:

### Step 1: Identify the structure of the compound
The given compound can be represented as follows:
- It has two amine groups (\( NH_2 \)) attached to a two-carbon chain (\( CH_2 - CH_2 \)).
- The structure can be written as \( NH_2 - CH_2 - CH_2 - NH_2 \).

### Step 2: Name the compound
The IUPAC name for this compound is ethane-1,2-diamine. This is because:
- The longest carbon chain contains two carbon atoms (ethane).
- There are two amine groups located at the first and second carbon atoms.

### Step 3: Determine the type of ligand
Next, we need to classify the ligand:
- A ligand can be classified based on its charge and denticity.
- Ethane-1,2-diamine is a neutral molecule (no overall charge), so it is classified as a neutral ligand.

### Step 4: Determine the denticity of the ligand
Denticity refers to the number of donor atoms in a ligand that can bind to a central metal atom:
- In ethane-1,2-diamine, there are two nitrogen atoms available for coordination (one from each \( NH_2 \) group).
- Therefore, the denticity of ethane-1,2-diamine is 2.

### Step 5: Classify the ligand as a chelating ligand
Since the denticity is 2, ethane-1,2-diamine is classified as a chelating ligand:
- Chelating ligands are those that can form multiple bonds to a single metal ion.
- In this case, both nitrogen atoms can coordinate to a metal center, making it a chelating ligand.

### Conclusion
Thus, the final classification of the compound \( H_2N - CH_2 - CH_2 - NH_2 \) is that it is a chelating ligand (specifically, ethane-1,2-diamine).

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