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ate maximum or minimum value of the func...

ate maximum or minimum value of the function ` y= 25x ^(2) +5- 10x `

A

`y _(min)=4`

B

` y _(max) =8`

C

`y _(min) =8`

D

`y _(max) =4`

Text Solution

Verified by Experts

The correct Answer is:
A
`(dy)/(dx) =50x-10 =0`
`x-1/5implies (d^(2)y)/( dx ^(2)) =50gt 0`
So y is minimum at `x=1//5`
`y_(""(min))=25xx(1)/(25)+ 5-10 xx1/5 =4`
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