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In PEE, value of K (max) is equal to K (...

In PEE, value of `K _(max)` is equal to `K _(0).` If frequency of light is doubled than `k _(max)` is `3K_(0)` is frequency is three times then calculate `K _(max)`

A

`K _(0)`

B

`3K_(0)`

C

`5K_(0)`

D

`5K_(0)`

Text Solution

Verified by Experts

The correct Answer is:
C
`K_(0) =hr -phi " "...(i)`
`3K_(0) =2hr -phi" "...(ii)`
`therefore phi = K_(o) impliesK _(max) =3hr -phi =6 K_(0) -K_(0) =5 K_(0)`
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