Three masses `M_(1), M_(2)` and `M_(3)` are lying on a frictionless table. The masses are connected by massless threads as shown. The mass `M_(3)` is pulled by a constant force F as shown. The tension in the thread between masses `M_(2)` and `M_(3)` is

Answer

A

Explanation

For body diagram of masses are
`therefore F = T_(1) = M_(3)a " "………(i)`
`T _(1) - T_(2) = M_(2)a " "….(ii)`
`T_(2) = M_(1)a" "…….(iii)`
Adding (i) , (ii) , and (iii) we get
`F = a(M_(1) + M_(2) + M_(3))`
`therefore a = (F)/((M_(1) + M_(2) + M_(3))) " ".......(iv)`
`T_(1) = (M_(1) + M_(2)) a = (M_(1) + M_(2)) F//M_(1) + M_(2) + M_(3)`