The excess pressure inside a soap bubble is twice the excess pressurre inside a second soap bubble. The volume of the first bubble is n times the volume of the second where n is

Options

A. 2
B. 1
C. 0.25
D. 4

Answer

C

Explanation

`Pex_(1) = 2Pex_(2) or (Pex_(1))/(Pex_(2)) = (2)/(1)`
`(V_(1))/(V_(2)) = ((r_(1))/(r_(2))^(3) = ((Pex_(2))/(Pex_(1))^(3) = ((1)/(2))^(3) = (1)/(8)`
` n = (1)/(8) = 0.125` (`because` given `v_(1) = nV_(2)`)