If 200 MeV energy is released per fissio...

If 200 MeV energy is released per fission of `._(92)U^(235)` How many fissions must occur per second to produce a power of 1m W?

A

`3.5xx10^(10)`

B

`4.2xx10^(11)`

C

`3.125xx10^(12)`

D

`3.125xx10^(13)`

Text Solution

Verified by Experts

The correct Answer is:

D

`n(200"Mev")=1"kW"`
`impliesn=(1000)/(200xx10^(6)xx1.6xx10^(-19))=3.125xx10^(13)`

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