Adding powdered Cu and Zn to a solution containing 1.0 M is each of `Cu^(​2+) and Zn^(​2+)` ions would result into the formation of :-

Options

A. More of `Cu and Zn^(​2+)`​ ions
B. More of `Zn and Cu^(​2+)`​ ions
C. More of Zn and Cu
D. More of `Zn​^(2+)​ and Cu^(​2+)`​ ions

Answer

A