Calculate kinetic energy of a gram molecule of oxygen at `127^(@)C`. Value of Boltzmann constant `= 1.381 xx 10^(-23) J K^(-1)`. Avogardro's number `= 6.022 xx 10^(23)` per gm-mole.

Calculate the kinetic energy of one mole of argon at 127^(@)C . Given,Boltzmann's constant, k_(B) = 1.381 xx 10^(-23) J "molecular"^(-1) K^(-1) . Avogardro numbe, N = 6.02 xx 10^(23) "mol"^(-1)

What is the K.E. of one mole of a gas at 237^(@)C ? Given Boltzamann's constant k = 1.38 xx 10^(-23) J //k , Avogadro number = 6.033 xx 10^(23) .

Calculate the most probable speed of a molecule of hydrogen at N.T.P. The Boltzmann constant is 1.38 xx 10^-23 J per degree and Avogadro's number is 6 xx 10^26 per kg mole.

Fill in the blanks: The value of Boltzmann's constant is 1.38 xx 10^-23 …………

Calculate the average translation kinetic energy of an ideal gas per molecule (epsilon) and per mole (E ) at 25^(@)C . (Boltzmann constant, k= 1.38 xx 10^(-23)JK^(-1) ).

Calculate (a) the average kinetic energy of translation of an oxygen molecule at 27^(@) C (b) the total kinetic energy of an oxygen molecule at 27^(@)C (c ) the total kinetic energy in joule of one mole of oxygen at 27^(@) . Given Avogadro's number = 6.02 xx 10^(23) and Boltzmann's constant = 1.38 xx 10^(-23) J//(mol-K) .

Calculate (a) the average kinetic energy of translation of an oxygen molecule at 27^(@) C (b) the total kinetic energy of an oxygen molecule at 27^(@)C (c ) the total kinetic energy in joule of one mole of oxygen at 27^(@) . Given Avogadro's number = 6.02 xx 10^(23) and Boltzmann's constant = 1.38 xx 10^(-23) J//(mol-K) .

Calculate the K.E. per mole of oxygen at 27^(@)C . Given N = 6.02 xx 10^(23), k = 1.38 xx 10^(-23) JK^(-1) .

At what temperature would the kinetic energy of a gas molecule be equal to the energy of photon of wavelength 6000Å ? Given, Boltzmann's constant, k = 1.38 xx 10^(-23) J .K^(-1) , Planck's constant, h = 6.625 xx 10^(-34) J.s