Solve the following simultaneous equation:
`30/(x-y)+44/(x+y)=10, 40/(x-y)+55/(x+y)=13`.

Explanation

To solve the simultaneous equations:

1. **Given Equations:**
\[ \frac{30}{x-y} + \frac{44}{x+y} = 10 \quad (1) \]
\[
\frac{40}{x-y} + \frac{55}{x+y} = 13 \quad (2)
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