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Given : square ABCD is cyclic. ...

Given `:`
`square ` ABCD is cyclic. `/_DCE ` is an exterior angle of `square ` ABCD.
To Prove `: /_DCE = /_BAD `
Complete the proof by filling the boxes.

Text Solution

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Proof `:` `/_DCE + /_BCD = 180^(@)` …..( Linear pair of angles ) …(1)
`square ` ABCD is cyclic
`:. /_BAD + /_BCD = 180^(@)` .... (Theorem of cyclic quadrilateral ) ..(2)
`:.` from (1) and (2) , we get
`/_DCE + /_BCD = /_ BAD +/_BCD `
`:. /_DCE = /_ BAD `
`:. /_DCE ~= /_BAD `.
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