`DeltaABC~DEF`.`A(DeltaABC) : A(DeltaDEF)=49 : 100`. Find the ratio of `AB : DE`.

DeltaABC~DeltaPQR . If A(DeltaABC)=25 , A(DeltaPQR)=16 find AB : PQ .

DeltaABC and DeltaDEF are equilateral triangles, A(DeltaABC):A(DeltaDEF)=1:2 If AB=4 then what is length of DE?

DeltaABC and DeltaDEF are equilateral triangles, A(DeltaABC) : A(DeltaDEF)= 1 :2 . If AB=4 then what is the length of DE ?

If DeltaABC ~ DeltaDEF such that A(DeltaABC) = 4A(DeltaDEF) and AC = 6 cm, then DF =

DeltaABC and DeltaDEF are equilateral triangles. If A(DeltaABC):A(DeltaDEF)=1:2 and AB=4 , find DE.

DeltaABC and DeltaDEF are equilateral triangles. If A(DeltaABC) :A(DeltaDEF)=1:2 and AB=4 , then what is the length of DE ?

It is given that DeltaABC ~ DeltaEDF and Area DeltaABC : Area DeltaDEF = 64: 25 . If AB = 16 cm, BC = 18 cm, CA= 20 cm. What is the value of EF (in cm)?

If DeltaABC ~ DeltaDEF and AB : PQ = 5 : 7 then write the ratio of A(DeltaABC) : A(DeltaPQR) .

Delta ABC~ DeltaDEF such that ar (Delta ABC)= 36 cm^(2) and ar (Delta DEF) 49 cm^(2) . Then, the ratio of their corresponding sides is

If DeltaABC~DeltaPQR,A(DeltaABC)=80, A (DeltaPQR)=125 , then fill in the blanks: (A(DeltaABC))/(A(Delta………..))=80/125:.(AB)/(PQ)=(square)/(square)