In the figure, seg `AB~=` seg `AC`, ray `CE` bisects `/_ACB` , ray `BD` bisects `/_ABC`. Prove that ray `ED||` side `BC`.

In the given figure,AB||EC,AB=AC and AE bisects /_DAC. Prove that:

In the figure, seg AB|| seg CD|| seg EF AC=1.5 , BD=10 , DF=6 then AE=?

In the given figure, DeltaABC is an isosceles triangle in which AB=AC and AE bisects angleCAD . Prove that AE||BC .

In DeltaABC ,ray BD bisects angleABC and ray CE bisects angleACB . If seg AB cong seg AC, then prove that ED abs() BC.

In the adjoining figure, the circle is the incircle of isosceles DeltaABC , where seg AB = seg AC. Prove that M bisects BC.

In the given figure, ray AE || ray BD, ray AF is the bisector of angleEAB and ray BC is the bisector of angleABD . Prove that lineAF || line BC.

Draw seg AB of length 5.7 cm and bisect it.

BD and CE are bisectors of /_B and /_C of an isosceles ABC with AB=AC. Prove that BD=CE

In the given figure, AB = AC and AD = AE. Prove that: BD = CE

In the adjoining figure,seg DE abs() side AC and seg DC abs() side AP. Prove that (BE)/(EC) = (BC)/(CP) .