In `DeltaABC`, `E` is the midpoint of the median `AD`. `BE` produced meets `AC` at `F`. Prove that `AF=(1/3)AC`

In Delta ABC,E is the midpoint of the median AD.BE produced meets AC at F. Prove that AF=((1)/(3))AC

In ABC,AD is the median through A and E is the mid-point of AD.BE produced meets AC in F (Figure).Prove that AF=(1)/(3)AC .

In the given figure, ABCD is a parallelogram and E is the midpoint of side BC. If DE and AB when produced meet at F, prove that AF = 2AB.

In a triangle ABC, AD is the median through A and E is the midpoint of AD, and BE produced meets AC at F. Then AF is equal to

In a DeltaABC, BD is the median to the side Ac, BD is produced to E such that BD = DE. Prove that AE is parallel to BC.

squareABCD is a parallelogram. P is the midpoint of side CD. Seg BP meets diagonal AC at X. Prove that 3AX=2AC .

In Delta ABC,D is the mid-pointpoint of BC and E is mid-point of AD.BE is produced to meet the side AC in F.Then BF is equal to

E is the mid-point of the median AD of DeltaABC. Line segment BE meets AC at point F when produce, prove that AF=1/3AC.

In Figure,AD, and BE are medians of ABC and BE||DF. Prove that CF=(1)/(4)AC .