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With the help of the information given in the figure, fill in the boxes to find `AB` and `BC`.
`AB=BC`………(Given)
`:./_BAC=/_BCA=square`
`:.AB=BC=squarexxAC`
`=squarexxsqrt(8)`
`=squarexx2sqrt(2)`
`=2`

Text Solution

Verified by Experts

`AB=BC`………(Given)
`:./_BAC=/_BCA=45^(@)`
`:.AB=BC=(1)/(sqrt(2))xxAC`
`=(1)/(sqrt(2))xxsqrt(8)`
`=(1)/(sqrt(2))xx2sqrt(2)`
`=2`
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