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In the figure, /LMN=/LKN=90^(@) seg MK...

In the figure, `/_LMN=/_LKN=90^(@)`
seg `MK bot ` seg `LN`.
Complete the following activity to prove `R` is the midpoint of seg `MK`.

Proof: In `DeltaLMN`, `/_LMN=90^(@)`
seg `MR bot` hypotenuse `LN`
`:.` by property of geometric mean,
`MR^(2)=squarexxRN`
In `DeltaLKN`, `/_LKN=90^(@)`
seg `KR bot ` hypotenuse `LN`
`:.` by property of geometric mean,
`KR^(2)=LRxxsquare`
From `(1)` and `(2)`, we get
`MR^(2)=square :. MR=square`.
`:. R` is the midpoint of seg `MK`.

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