Home
Class 10
MATHS
In the figure, seg AD bot side BC and B-...

In the figure, seg `AD bot` side `BC` and `B-D-C`, then prove `AB^(2)-BD^(2)=AC^(2)-CD^(2)`.

Promotional Banner

Topper's Solved these Questions

  • PYTHAGORAS THEOREM

    NAVNEET PUBLICATION - MAHARASHTRA BOARD|Exercise Assignment 3.5|5 Videos

  • PYTHAGORAS THEOREM

    NAVNEET PUBLICATION - MAHARASHTRA BOARD|Exercise EXAMPLES FOR PRACTICE ( 1 MARK MULTIPLE CHOICE QUESTIONS )|11 Videos

  • PYTHAGORAS THEOREM

    NAVNEET PUBLICATION - MAHARASHTRA BOARD|Exercise Assignment 3.3|9 Videos

  • PROBABILITY

    NAVNEET PUBLICATION - MAHARASHTRA BOARD|Exercise ASSIGNEMENT 5.4|12 Videos

  • QUADRATIC EQUATION

    NAVNEET PUBLICATION - MAHARASHTRA BOARD|Exercise CHALLENGIN QUESTIONS|2 Videos

Similar Questions

Explore conceptually related problems

In DeltaABC , seg AD bot seg BC , DB=3CD . Prove that 2AB^(2)=2AC^(2)+BC^(2) .

See the given figure. In DeltaABC," seg "ADbot" seg "BC. Prove that: AB^(2)+CD^(2)=BD^(2)+AC^(2)

In fig.if ,prove that AB^(2)+CD^(2)=BD^(2)+AC^(2)

In obtuse angled DeltaABC , /_B gt90^(@) . If seg Adbot ray CB and D-B-C , then prove that AC^(2)=AB^(2)+BC^(2)+2BC*DB .

In DeltaABC, if M is the midpiont of BC and seg AM bot seg BC, then prove that prove that AB^(2)+AC^(2)=2AM^(2)+2BM^(2).

In DeltaABC , /_C is an acute angle, seg AD bot seg BC . Prove AB^(2)=BC^(2)+AC^(2)-2BCxxDC by completing the following activity. Let AB=c , AC=b , AD=p , BC=a , DC=x :.BD=a-x In DeltaADB , by Pythagoras theorem, c^(2)=(a-x)^(2)+square c^(2)=a^(2)-2ax+x^(2)+square ........... (1) In DeltaADC , by Pythagoras theorem, b^(2)=p^(2)+square p^(2)=b^(2)-square .......... (2) Substituting value of p^(2) from (2) in (1) c^(2)=a^(2)-2ax+x^(2)+square c^(2)=a^(2)+b^(2)-square :.AB^(2)=BC^(2)+AC^(2)-2BCxxDC .

In the given figure if AD bot BC prove that AB^(2)+CD^(2)= BD^(2) +AC^(2)

In Figure 2,AD perp BC. Prove that AB^(2)+CD^(2)=BD^(2)+AC^(2)