Home
Class 10
MATHS
If P (-6,-3) and Q (-1, 9), then complet...

If P (-6,-3) and Q (-1, 9), then complete the following
acitvity to find PQ .

Text Solution

Verified by Experts

Let `P(x_(1),y_(1)) " and " Q (x_(2) , y_(2))`
` x_(1) = - 6, y_(1) = - 3, x_(2) = - 1 " and " y_(2) = 9`
`PQ = sqrt(square) " "` [Distance formula]
`therefore PQ = sqrt(square+square) `
`therefore PQ = sqrt(square)`
` therefore PQ = square`
Actively :
`sqrt((x_(2)-x_(1))^(2)+(y_(2)-y_(1))^(2))` ...[Distance formula]
`:. PQ =sqrt(25+144)`
`:. PQ=sqrt(169)`
`:. PQ=13`
Promotional Banner

Topper's Solved these Questions

  • COORDINATE GEOMETRY

    NAVNEET PUBLICATION - MAHARASHTRA BOARD|Exercise 6.4 1mark each|9 Videos
  • COORDINATE GEOMETRY

    NAVNEET PUBLICATION - MAHARASHTRA BOARD|Exercise 6.5 1mark each|3 Videos
  • COORDINATE GEOMETRY

    NAVNEET PUBLICATION - MAHARASHTRA BOARD|Exercise 6.2 1mark each|5 Videos
  • CIRCLE

    NAVNEET PUBLICATION - MAHARASHTRA BOARD|Exercise Challenging Questions|10 Videos
  • FINANCIAL PLANNING

    NAVNEET PUBLICATION - MAHARASHTRA BOARD|Exercise ASSIGNEMENT 4.4|4 Videos

Similar Questions

Explore conceptually related problems

In the given figure,ray PQ touches the circle at point Q. PQ=12, PR=8, complete the following activity to find PS and RS.

(A) Complete any one out of two activities : Complete the following activity to show the points P(3,0) Q (6,-2) and R (-3,4) are collinear . Let P( 3,0) = (x_(1) ,y_(1)) Q (6,-2)= (x_(2),y_(2)) R (-3,4) = (x_(3) , y_(3)) slope of a line PQ = (y_(2)-square)/(x_(2) -x_(1)) = (-2-0)/(6-3)= square " " ...(1) slope of line QR = (y_(3) -y_(2))/(x_(3)-x_(2))= (square -(-2))/(-3-6) = (4+2)/(-9) = 6/(-9) = square " " ... (2) :. from (1) and (2) the slopes of lines PQ and QR are square and point square is the :. points P,Q and R are collinear .

If P=(1,2,3,4,5,6,7) and Q=(2,5,8,9) , then find P cup Q .

P(-3, 7) and Q(1, 9) are two points. Find the point R on PQ such that PR:QR = 1:1 .

If q = 5 and p = -3 , then find the value of the following expressions. 8q + 9p – 17

If P=(1,2,3,4,5,6,7) and Q=(2,5,8,9) , then find P-Q.

If P(3,2,-4),Q(5,4,-6) and R(9,8,-10) are collinear, then R divides PQ in the ratio

If P=(1,2,3,4,5,6,7) and Q=(2,5,8,9) then find P cap Q .

The coordinates of the points P and Q are respectively (4,-3) and (-1,7). Find the abscissa of a point R on the line segment PQ such that (PR)/(PQ)=(3)/(5) .

If P(3, 2, -4), Q(5, 4, -6) and R(9, 8, -10) are collinear, then R divides PQ in the ratio