If the points A(-4, -2) , B (-3,-7) , C(3,-2) and D(2,3) are
joined serially , find the type of quadrilateral ABCD by completing
the following activity.

Explanation

Slope of line AB `= (-7-(-2))/(-3-(-4))= square`
Slope of line `BC = (-2-(-7))/(3-(-3)) = square `
Slope of line `CD = (3-(-2))/(2-3) = square `
Slope of line ` AC = (3-(-2))/(2-(-4)) = square `
In `square ABCD ` , slopes of opposite are `square`
` therefore square ABCD "is a " square`
Activity :
Slope of line ` AB= (-7- (-2))/(-3-(-4)) = -5`
Slope of line ` BC = (-2 -(-7))/(3-(-3)) = (5)/(6)`
Slope of line` CD = (3-(-2))/(2-3) = -5`
Slope of line ` AD = (3 - (-2))/(2-(4)) = (5)/(6)`
In` square ABCD ` , slopes of opposite sides are equal
` therefore square ABCD ` is a paralelogram .