Solve the following activity and find the value of `6 tan^(2)theta-6/(cos ^(2) theta)`

Explanation

`6 tan^(2)theta-t/(cos^(2) theta)`
`=(tan^(2) theta-1/(square))`
`=6 (tan^(2)theta-square)`……..(Writing the reciprocal)
`=6(square)`
`=square`
Activity: `6 tan^(2) theta-6/(cos^(2) theta)`
`=6(tan^(2) theta-1/(cos^(2) theta))`
`=(tan^(2) theta-sec^(2)theta)` ...........(Writing the reciprocal)
`=6(-1)`.............`(1+tan^(2) theta=sec^(2) theta)`
`-6`