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Prove that sqrt[[1-sintheta]/[1+sintheta...

Prove that `sqrt[[1-sintheta]/[1+sintheta]]=sectheta-tantheta`

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Proof: `LHS=sqrt((1-sin theta)/(1+sin theta))`
`=sqrt(((1-sin theta))/((1+sin theta))xx((1-sin theta))/((1-sin theta)))`
`=sqrt(((1-sin theta)^(2))/(1^(2)-sin^(2)theta))`
`=sqrt(((1-sin theta)^(2))/(cos^(2) theta))`………..`(sin^(2) theta+cos^(2)theta=1)`
`=1-(sin theta)/(cos theta)`
`=1/(cos theta)-(sin theta)/(cos theta)`
`=sec theta-tan theta`.........`[sec theta=1/(cos theta), tan theta=(sin theta)/(cos theta)]`
`=RHS`
`:.sqrt(((1-sin theta))/((1+sin theta)))=sec theta-tan theta`
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NAVNEET PUBLICATION - MAHARASHTRA BOARD-TRIGONOMETRY-ASSIGNMENT
  1. Solve the following activity and find the value of 6 tan^(2)theta-6/(c...

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  2. Proove: (sin^(2)theta)/(cos theta)+cos theta=sec theta

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  3. Prove that sqrt[[1-sintheta]/[1+sintheta]]=sectheta-tantheta

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  4. Complete the following activity by filling the boxes sin^(2) theta+c...

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  5. Prove that sec theta+tan theta=(cos theta)/(1-sin theta)

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  6. Prove : cot^(2) theta-tan^(2)theta=cosec^(2)theta-sec^(2)theta

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  7. If tan theta=1, then (sin theta+cos theta)/(sec theta+cosec theta)=

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  8. Prove :(sec theta-cos theta)(cot theta+tan theta)=tan .sec theta

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  9. Prove cot theta+tan theta=(cosec theta)(sec theta) by completing the f...

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  10. Prove: (tan theta)/(sec theta-1)=(tan theta+sec theta+1)/(tan theta+se...

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  11. When observer at a distance of 12m from a tree looks at the top of the...

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  12. From the top of a lighthouse, an observer looking at a boat makes an ...

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  13. If 1/(sin^(2)theta)-1/(cos^(2) theta)-1/(tan^(2)theta)-1/(cot^(2)theta...

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  14. If sec theta=13/12, find the values of other trigonometric ratios.

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  15. If sqrt(3) tan theta=3 sin theta and theta!=0 then find the value of s...

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  16. Prove: sec^4A(1-sin^4A)-2tan^2A=1

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  17. Prove : 2(sin^(6)theta+cos^(6)theta)-3(sin^(4)theta+cos^(4)theta)+1=0.

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  19. A ladder on the platform of a firebrigade van can be elevated at an an...

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  20. While landing at an airport, a pilot made an angle of derpession of 20...

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