संख्या `("cos"(pi)/(6) + i "sin"(pi)/(6))` का मुख्य कोणांक ज्ञात कीजिए।

If z = cos (pi)/(4) + i sin (pi)/(6) , then

If z=cos((pi)/(4))+i sin((pi)/(6)), then

if z = cos ""pi/4 + i sin""pi/6 then

if z = cos ""pi/4 + i sin""pi/6 then

" (a) "int_(0)^( pi/6)sqrt(1-sin2x)dx" का मान ज्ञात कीजिए "

cos^(2)(""(pi)/(6) + theta ) -sin^(2)""((pi)/(6) - theta ) =

z = (1+cos6 pi)+i sin6 pi

One of the value of ("cos"(pi)/(6) +i "sin"(pi)/(6))^((1)/(2)) + ("cos"(pi)/(6)- i "sin"(pi)/(6))^((11)/(2)) is

Find the rectangular form of the complex numbers. (cos" " (pi)/(6) + i sin" " (pi)/(6)) (cos" " (pi)/(12) + i sin" " (pi)/(12))