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A Solution is prepared by dissolving ce...

A Solution is prepared by dissolving certain amount of solute in 500 g water. The % by mass of a solutions is 2.38 . Calculate mass of the solute.

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The correct Answer is:
Mass of the solute =12. 19 g
Given : `W_(1)`= Mass of a solvent (water) = 500 g
`W_(2)` Mass of a solute =?
% by mass = % `(W//W) = 2. 38`
Let mass of the solute `=W_(2) =x g`
`:.` Mass of the solution `= W_(1) + W_(2) = (500 + x) g`
Now per cent by mass of solute `= ("mass of solute")/("mass of solution") xx 100`
`= ("mass of solute")/("mass of solvent + mass of solute") xx 100`
`:. 2.38 = (X )/((500 + X)) xx 100`
`:. 2. 38 (500 + X) =100 x`
`:. 2.38 xx 500 + 2.38 X =100 x`
`:. 1190 + 2.38 X = 100 x`
`:. 100 x -2.38 x= 1190`
`:. (100 -2.38) x= 1190`
`:. 97 .62 x = 1190`
`:. x = (1190)/(96.62) =12.19`
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