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Calculate mole fraction of HCI in a ...

Calculate mole fraction of HCI in a solution containing 24.8% of HCI by mass.

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The correct Answer is:
Mole fraction HCI= 0.1398
Given : % by weight of HCI = 24.8 ,
Mole fraction of HCI= `X_(HCI)= ?`
Consider 100 gram HCI solution .
`:.` Weight of a solute (HCI) =24.8 g
Weight of a solvent (water) = 100 -24.8 = 75.2 g
`:. ` Moles of solvent = `n_(H_(2)O) = .(W_(H_(2)O))/(M_(H_(2)O))=(75.2)/(18) =4.178 mol H_(2)O`
Moles of solute `=n_(H_(2)O) =(W_(H_(2)O))/(36.5) =(24.8)/(36.5)=0.6795 mol`
`:. ` Total moles in solution `= n_(H_(2)O) + n_(HCI)`
`=4. 178 + 0.6795 =4. 8575`
Mole fraction of HCI `X_("HCI") =("moles of HCI")/("total moles in solution")`
`= (0.6795)/(4.8575)= 0.1398`
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