Calculate the osmotic pressure of 6% sucrose `(C_(12) H_(22) O_(11))` solution at 300 K
`(R 8. 314 J mol^(-1) K^(-1))`

Answer

Osmotic pressure of the solution `=4.374 xx 10^(5) Nm^(-2)`

Explanation

Given : W = Amount of sucrose =`6g = 6.0 xx 10^(3) kg `
M= Molecular weight of sucrose `=(C_(12) H_(22) O_(11))`
`=(12 xx 12 + 22 xx 1+ 11 xx 16)`
`=342 "mol"^(-1)`
`= 342 xx 10^(-3) kg "mol"^(-1)`
n= Number of the moles of sucrose `= (W)/(M)= (6.0 xx 10^(-3))/(352 xx 10^(-3))`
`=0.01754 "mol"`
V= Volume of the solution =100 ml = 0.1 `dm^(3)`
`=0.1 xx 10^(-3) m^(3)`
T= Temperature of the solution =300 K
`R= 8.314 J "mol"^(-1) K^(-1)`