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Three moles of the ideal gas are exp...

Three moles of the ideal gas are expanded isothermally from a volume of 300 `cm^(3)` to 2.5 L at 300 K against a pressure of 1.9 atm. Calculate the work done in L and and joules .

Text Solution

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The correct Answer is:
Work of expansion =W= - 4.18 L atm
`=- 423. 4J`
Number of moles of a gas = n= 3 mol
Initial volume `=V_(1) = 300 cm^(3) = 0.3 L (or dm^(3))`
Final volume `= V_(2) = 2.5 L`
External pressure `= P_(ex) = 1.9 atm `
Temperature = T = 300 K
Since the expansion takes place against constant pressure it is irreversible process and work is given by
`W=- P_("ex") (V_(2)-V_(1))`
=- 1.9 (2.5 -0.3)
`=- 4.18 L atm `
Now , 1 L atm = 101 . 3 J
`:. W= - 4.18 xx 101 .3 =- 423 .4 J`
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