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The specific conductance (or conduct...

The specific conductance (or conductivity ) of 0.014 M NaBr solution is `3.16 xx 10^(-4) S cm^(-1)` .Find the molar conductivity of the solution .

Text Solution

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The correct Answer is:
Molar conductivity `= ^^_(m) = 22.57 S cm^(2) mol^(-1)`
`" or " ^^ _(m) =22.56 Omega^(-1) cm^(2) mol^(-1)`
Concetration of the solution = 0.014 M NaBr
Specific conductance = conductivity = k
`=3.16 xx 10^(-4) S cm^(-1) ( or Omega^(-1) cm^(-1))`
Molar conductivity = `^^_(m) = ?`
`^^_(m) = (k xx 1000)/( C)`
` =(3.16 xx 10^(-1) xx 1000)/( 0.014)`
`mol L ^(-1)`
`= 22.57 S cm^(2) mol^(-1) (or Omega^(-1) cm^(2) mol^(-1))`
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