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A conductivity cell filled with 0.02 M...

A conductivity cell filled with 0.02 M `AgNO_(3)` gives at `25^(@) C` resistance of 947 ohms. If the cell constant is 2.3 `cm^(-1)` . What is the molar conductivity of 0.02M `AgNO_(2)" at " 25^(@)C`

Text Solution

Verified by Experts

The correct Answer is:
Molar conductivity `=^^_(m) = 121.5 Omega^(-1) cm^(2) mol^(-1)`
Given : Concetration = C = 0.02 M `AgNO_(2)`
Resistance of solution = `R_("soln") = 947 Omega`
Cell constant `= b = 2.3 cm^(-1)`
Molar conductivity = `^^_(m) = ?`
Conductivity of soln `= (" cell constant ")/(R_("soln ")) = ( b)/(R_("soln ")) = (23)/(947)`
`= 0.002429 Omega^(-1) cm^(-1)`
`"Molar conductivity " ^^_(m) = (kxx 1000)/( C) = (0.002429 xx 1000)/(0.02)`
`= 121. 5 Omega^(-1) cm^(2) mol^(-1)`
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