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Boiling point of a solvent is 80.2.^(...

Boiling point of a solvent is `80.2.^(@)C` When 0.419 g of the solute of molar mass 252 .4 g `mol^(-1)` is dissolved in 75 g of the above solvent the boiling point of the solution is found to be 80. 256 `.^(@)C`
Final the molal elevation constant

Text Solution

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`K_(b)= 2.53 K kg mol^(-1)`
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