In the case of thorium `(A = 232 and Z = 90)`, we obtain an isotope of lead `(A = 208 and Z = 82)` after some radiactive disintegrations. The number of `alpha` and `beta` particle emitted are respectively.

The end product of decay of ""_(90)Th^(232) is ""_(82)Pb^(208) . The number of alpha and beta particles emitted are respectively

In a radioactive reaction ._92 X^232 rarr ._82 Y^204 , the number of alpha- particle emitted is.

Atomic mass number of an element is 232 and its atomic number is 90 . The end product of this radiaoctive element is an isotope of lead (atomic mass 208 and atomic number 82 .) The number of alpha -and beta -particles emitted are.

Atomic mass number of an element is 232 and its atomic number is 90 . The end product of this radiaoctive element is an isotope of lead (atomic mass 208 and atomic number 82 .) The number of alpha -and beta -particles emitted are.

Atomic mass number of an element is 232 and its atomic number is 90 . The end of radioactive disintegration we obtain an isotope of lead with A = 208 and Z = 82 . Then the number of emitted alpha and beta particles are

The end product of the decay of ""_(90)Th^(232) is ""_(82)Pb^(208) . The number of alpha and beta particles emitted are respectively ...............

A radioactive disintegration of ""_(90)Th^(232) yields ""_(82)Pb^(208) in the end . The number of alpha and beta -particle emitted will be