For an equilibrium reaction, the rate constants for the forward and the backward reaction are `2.38xx10^(-4)` and `8.15xx10^(-5)`, respectively. Calculate the equilibrium constant for the reaction.

In a reversible reaction the rate constants of the forward and the backward reactions are 4.8xx10^(-5)s^(-1)and1.2xx10^(-4)s^(-1) respectively. Calculate the equilibrium constant.

For the reaction , A+2B hArr 2C , the rate constant for the forward and the backward reactions are 1xx10^(-4) and 2.5xx10^(-2) respectively.The value of equilibrium constant, K, for the reaction would be :

Find the value of equilibrium constant if the rate constante for the forward and backward reactions are , 2.38 xx 10^(-4) " and " 8.15 xx 10^(-4) respetively.

For the reaction A+B hArr C , the rate constants for the forward and the reverse reactions are 4xx10^(2) and 2xx10^(2) respectively. The value of equilibrium constant K for the reaction would be

For the reaction A+B hArr C , the rate constants for the forward and the reverse reactions are 4xx10^(2) and 2xx10^(2) respectively. The value of equilibrium constant K for the reaction would be