From a certain apparatus, the diffusion rate of hydrogen has an average value of `28.7 cm^(3) s^-1`.The diffusion of another gas under the same conditions is measured to have an average rate `7.2 cm^-3s^-1`.Identify the gas .[Hint :Use Graham’s law of diffusion: `R_(1)//R_(2)=(M_(2)/M_(1))^"1/2"` ,where `R_(1),R_(2)` are diffusion rates of gases 1 and 2, and `M_1` and `M_2` their respective molecular masses. The law is a simple consequence of kinetic theory.]

From a certain apparatus,the diffusion rate of hydrogen has an average value of 28.7 cm^3s^(-1) .The diffusion of another gas under the same conditions is measured to have an average rate of 7.2 cm^3s^(-1) .Identify the gas.

From a certain apparatus, the diffusion rate of hydrogen has an average value of 28.7 cm^3 s^-1 . The diffusion of another gas under the same conditions is measured to have an average rate of 7.2 cm^3 s^-1 . Identify the gas

From a certain apparatus, the diffusion rate of hydrogen has an average value of 28.7 cm^(3) s^(-1) . The diffusion of another gas under the same condition is measured to have an average rate of 7.2 cm^(3) s^(-1) . Identify the gas.

From a certain apparatus, the diffusion rate of hydrogen has an average value of 28.7 cm^(3) s^(-1) . The diffusion of another gas under the same condition is measured to have an average rate of 7.2 cm^(3) s^(-1) . Identify the gas.

From a certain apparatus, the diffusion rate of hydrogen has an average value of 28.7 cm^(3) s^(-1) . The diffusion of another gas under the same condition is measured to have an average rate of 7.2 cm^(3) s^(-1) . Identify the gas.

From a certain appartus the diffusion rate of hydrogen has an average value of 28.7 cm^2.s^-1 The diffusion of another gas under the same conditions is measured to have an average rate of 7.2 cm^3.s^-1 Identify the gas.

From a certain apparatus, the diffusion rate of hydrogen has an average value of 28.7 cm^(3) s^(-1) . The diffusion of another gas under the same conditions is measured to have an average rate of 7.2 cm^(3) s^(-1) . Identify the gas. [Hint : Use Graham's law of diffusion: R_(1)//R_(2) = (M_(2) //M_(1) )^(1//2) , where R_(1), R_(2) , are diffusion rates of gases 1 and 2, and M_(1) and M_(2) their respective molecular masses. The law is a simple consequence of kinetic theory.]

From a certain apparatus, the diffusion rate of hydrogen has an average value of 28.7 cm^(3) s^(-1) . The diffusion of another gas under the same conditions is measured to have an average rate of 7.2 cm^(3) s^(-1) . Identify the gas. [Hint : Use Graham's law of diffusion: R_(1)//R_(2) = (M_(2) //M_(1) )^(1//2) , where R_(1), R_(2) , are diffusion rates of gases 1 and 2, and M_(1) and M_(2) their respective molecular masses. The law is a simple consequence of kinetic theory.]