If `E=E_1,E_2,E_3,E_4,E_5 and P(E_1)=(95)/(100),P(E_2|E_1)=94/99,P(E_3|E_1E_2)=93/98,P(E_4|E_1E_2E_3)=92/97 and P(E_5|E_1E_2E_3E_4)=91/96,` then `P(E)` equals

If P(E_2)=1/9 , P(E_2//E_1)=3/5 , P(E_1//E_2)=3/4 then find P(E_1) .

If P(E_(1))=1//2, P(E_(2))=1//2" and "P(A//E_(1))=1//2, P(A/E_(2))=1//4 . Find P(E_(1)//A) .

if E_(1) and E_(2) are two events such that P(E_(1))=(1)/(4),P((E_(2))/(E_(1)))=(1)/(2) and P=((E_(1))/(E_(2)))=(1)/(4)

If E_(1) and E_(2) are two events such that P(E_(1))=1//4 , P(E_(2)//E_(1))=1//2 and P(E_(1)//E_(2))=1//4 , then

If E_(1) and E_(2) are two events such that P(E_(1))=1//4 , P(E_(2)//E_(1))=1//2 and P(E_(1)//E_(2))=1//4 , then

If E_(1) and E_(2) are two events such that P(E_(1))=1//4 , P(E_(2)//E_(1))=1//2 and P(E_(1)//E_(2))=1//4 , then

If E_(1) and E_(2) are two events such that P(E_(1))=1//4 , P(E_(2)//E_(1))=1//2 and P(E_(1)//E_(2))=1//4 , then

consider an event E=E_(1)capE_(2)capE_(3) find the value of P(E) if P(E_(1))=2/5,P(E_(2)/E_(1))=1/5 and P(E_(3)/(E_(1)E_(2)))=1/10

A sample space consists of 9 elementary event E_1, E_2, E_3 ..... E_8, E_9 whose probabilities are P(E_1) = P(E_2) = 0. 08 , P(E_3) = P(E_4)=P(E_5) = 0. 1 , P(E_6) = P(E_7) = 0. 2 , P(E_8) = P(E_9) = 0. 07 . Suppose A = {E_1,E_5,E_8} , B = {E_2, E_5, E_8, E_9} . Compute P(A) , P(B) and P(AnnB) . Using the addition law of probability, find P(AuuB) . List the composition of the event AuuB , and calculate, P(AuuB) by adding the probabilities of the elementary events. Calculate P(barB) from P(B) , also calculate P(barB) directly from the elementary events of barB .