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" 22."quad 4/4A=[[2,-3],[-4,1]]," Ta adj...

" 22."quad 4/4A=[[2,-3],[-4,1]]," Ta adj "(3A^(2)+12A)sqrt(actan^(3))

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if A=[[2,-3],[-4,1]] then adj(3A^2+12A)=?

if A=[[2,-3],[-4,1]] then (3A^2+12A)=?

if A=[[2,-3],[-4,1]] then (3A^2+12A)=?

if A=[[2,-3],[-4,1]] then (3A^2+12A)=?

if A=[[2,-3],[-4,1]] then (3A^2+12A)=?

if A=[[2,-3-4,1]] then (3A^(2)+12A)=?

If A=[(2,-3),(-4,1)] , then adj (3A^(2)+12 A) is equal to

If A=[(2,-3),(-4,1)] , then adj (3A^(2)+12 A) is equal to

If A=[[3,2],[1,4]], then A(adj A)=

If A=|{:(,2,-3),(,-4,1):}| then adj (3A^(2)+12A) is equal to