0 तथा 0.1 के बीच 9 परिमेय संख्याएँ ज्ञात कीजिए।

Explanation

यहाँ है `" "x=0, y = 0.1" तथा " n = 9`
तब `" "d=(y-x)/(n+1)=(0.1-0)/(9+1)=(0.1)/(10)=0.01`
0 तथा 0.1 के बीच अभीष्ट संख्याएँ हैं
`(x+d),(x+2d), (x+3d)…(x+9d)`
`rArr" "0.01, 0.02, 0.03,... 0.09`
`rArr" "(1)/(100),(2)/(100),(3)/(100),...,(9)/(100)`
`rArr" "(1)/(100),(1)/(50),(3)/(100),(1)/(25),(1)/(20),(3)/(50),(7)/(100),(2)/(25),(9)/(100)`
अतः अभीष्ट संख्याएँ हैं, `" "(1)/(100),(1)/(50),(3)/(100),(1)/(25),(1)/(20),(3)/(50),(7)/(100),(2)/(25)" तथा "(9)/(100)`